Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you evaluate the integral #int 2^x/(2^x+1)#?

1 Answer

Ananda Dasgupta

Mar 23, 2018

# ln(2^x+1)/ln 2+C#

Explanation:

Since #d/dx(2^x+1)=2^x ln 2#, we have

#int 2^x/(2^x+1)dx = 1/ln 2 int {d(2^x+1)}/(2^x+1) = ln(2^x+1)/ln 2+C#

Related questions

See all questions in Integration by Parts

Impact of this question

3240 views around the world

You can reuse this answer
Creative Commons License