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How do you evaluate the expression r(p+3) + q(p-1),for p=7,q=4,r=3?

1 Answer

Sep 10, 2015

Replace each variable with its value and evaluate arithmetically to get #54#

Explanation:

Given #color(red)(p=7)#, #color(blue)(q=4)#, and #color(green)(r=3)#

#color(green)(r)(color(red)(p)+3)+color(blue)(q)(color(red)(p)-1)#
#color(white)("XXX")#becomes
#color(green)(3)(color(red)(7)+3)+color(blue)(4)(color(red)(7)-1)#

#=3(10)+4(6)#

#=30+24#

#=54#

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