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How do you evaluate #x^2+2x-1# when #x=2#?

1 Answer

Oct 27, 2014

All you need to do is replace #x# with #2# since it has been given #x=2#.

So,
#x^2-2x-1 = (2)^2+2(2)-1 = 4+4-1 = 7#

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