How do you evaluate log_8 (4) + log_8 (16) ?

1 Answer
Alan P.
May 12, 2016

log_8(4)+log_8(16)=color(green)(2)

Explanation:

Remember that in general
color(white)("XXX")log_b(a)+log_b(c)=log_b(ac)

So
color(white)("XXX")log_8(4)+log_8(16)=log_8(64)

and since 8^2=64
color(white)("XXX")log_8(64)=2

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