How do you evaluate #log_5 25#?

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Answer 1 · 2016-08-12T08:51:03

#log_5 25 = 2#

Written in this form, the question being asked is..

"To what power must 5 be raised to give 25?"

Or, "How can 5 become 25 by raising to a power?"

We know that #5^2 = 25#, so we can say

#log_5 25 = 2#

We can also change log form into index form:

#log_5 25 = x # becomes # 5^x = 25#

So #x = 2#