How do you evaluate #ln(e) - 3 ln(1/e) - ln(e^3)#?

1 Answer
MrsRudolph221
Mar 29, 2016

If you know that "ln" is the natural logarithm, you might know that is a logarithm in base "e".

Explanation:

#ln(e) - 3ln(1/e) - ln(e^3)# = #1 - 3(-1) - 3# = 1.

Remember, the answer to a log is the power (exponent).
#ln(e) = 1# since e is to the first power.
#3ln(1/e) = 3(-1)# since e is to the -1 power.
and #ln(e^3)=3# since e is to the third power.

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