How do you evaluate (e^0.24)^2?

1 Answer
Aug 20, 2016

(e^0.24)^2=1.616.

Explanation:

Let x=(e^0.24)^2

:. x=e^((0.24)(2))=e^0.48

To find its numerical value, let us use Log-table (base 10).

x=e^0.48

rArr logx=loge^0.48=0.48loge

rArr logx=(0.48)(0.4343)=0.208464~=0.2085

rArr x=Antilog0.2085=1.616

Hence, (e^0.24)^2=1.616.