How do you evaluate 3^ln0.2?

Feb 24, 2017

${3}^{\ln 0.2} = 0.171$

Explanation:

Let ${3}^{\ln 0.2} = x$. Taking natural log on both sides, we get

$\ln 0.2 \ln 3 = \ln x$ and hence

$x = {e}^{\ln 0.2 \ln 3}$

= ${e}^{- 1.609 \times 1.0986}$

= ${e}^{- 1.76815} = 0.171$