How do you evaluate $2 [3 (7 - 5) + 4 (8 + 2)]$ $2[3(7-5) + 4(8+2)]$ ?

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Answer 1 · 2018-03-04T06:55:08

Using PEMDAS

$2 [3 (7 - 5) + 4 (8 + 2)]$ $2[3(7 - 5) + 4(8 + 2)]$

P - parentheses which are the brackets.

E - exponents

M - multiplication

D - division

A - addition

S - multiplication

We start with the parentheses..

$2 [3 (2) + 4 (10)]$ $2[3(2) + 4(10)]$

$= 2 [6 + 40]$ $=2[6 + 40]$

$= 2 [46]$ $=2[46]$

$= 92$ $=92$

Answer 2 · 2018-03-04T07:08:25

$92$ $92$

Start with the inner brackets and simplify each to a single answer.

$2 [3 (7 - 5) + 4 (8 + 2)]$ $2[3(color(blue)(7-5))" "+" "4(color(red)(8+2))]$

$= 2 [3 (2) + 4 (10)] \leftarrow$ $=2[3(color(blue)(2))" "+" "4(color(red)(10))]" "larr$ multiply to remove the brackets

$= 2 [6 + 40] \leftarrow$ $=2[color(blue)(6)" "+" "color(red)(40)]" "larr$ simplify inside the square brackets

$= 2 [46] \leftarrow$ $=2[color(purple)(46)]" "larr$ multiply to remove the square brackets

$= 92$ $=92$

It may seem that the usual order of operations is not being followed here because we do:

However, all of these are just to get rid of the brackets.
There is only only term but we work from the inner brackets, outwards.

How do you evaluate 2[3(7−5)+4(8+2)]2[3(7-5) + 4(8+2)]?