How do you evaluate 10 log18 - log3?

1 Answer
Alan P.
Dec 21, 2015

10log(18)-log(3)=log(18^10/3)

Explanation:

Remember

  1. mlog(n) = log(n^m)
  2. log(a)-log(b) = log(a/b)

Therefore
color(white)("XXX")10log(18)-log(3)

color(white)("XXX")=log(18^10)-log(3)

color(white)("XXX")=log(18^10/3)

This could be evaluated using a calculator as:
color(white)("XXX")=12.0756

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