How do you divide $(x^{3} + 3 x^{2} - 5 x + 5) \div (x + 4)$ $(x^3+3x^2-5x+5)÷(x+4)$ ?

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Answer 1 · 2015-10-07T01:09:54

$x^{2} - x - 1$ $x^2-x-1$ Remainder: $9$ $9$

Two ways to perform this division are demonstrated below:
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How do you divide (x^3+3x^2-5x+5)÷(x+4)(x3+3x2−5x+5)÷(x+4)(x^3+3x^2-5x+5)÷(x+4)?