How do you divide $\frac{x^{3} - 2 x^{2} + 2 x - 9}{x - 2}$ $(x^3-2x^2+2x-9) / (x-2)$ using polynomial long division?

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How do you divide $\frac{x^{3} - 2 x^{2} + 2 x - 9}{x - 2}$ $(x^3-2x^2+2x-9) / (x-2)$ using polynomial long division?

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Answer 1 · 2015-12-01T12:52:34

$x^{2} + 2$ $x^2+2$ with remainder $(- 5)$ $(-5)$
(see below for actual polynomial long division)

Explanation:

${: (,,x^2,,+2,), (,,"----","----","----","----"), (x-2,")",x^3,-2x^2,+2x,-9), (,,x^3,-2x^2,,), (,,"----","----","----","----"), (,,,,+2x,-9), (,,,,"----","----"), (,,,,,-5) :}$

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How do you divide $\frac{x^{3} - 2 x^{2} + 2 x - 9}{x - 2}$ $(x^3-2x^2+2x-9) / (x-2)$ using polynomial long division?

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Explanation:

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How do you divide (x^3-2x^2+2x-9) / (x-2) x3−2x2+2x−9x−2(x^3-2x^2+2x-9) / (x-2) using polynomial long division?

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Explanation:

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How do you divide $\frac{x^{3} - 2 x^{2} + 2 x - 9}{x - 2}$ $(x^3-2x^2+2x-9) / (x-2)$ using polynomial long division?