How do you divide #(-4x^3 + 20x^2 + 144x)# by #(x -9)#?

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How do you divide #(-4x^3 + 20x^2 + 144x)# by #(x -9)#?

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Answer 1 · 2015-10-22T12:47:13

One method would be to use synthetic division, to get
#color(white)("XXX")(-4x^2-16x)#

Explanation:

#{: (,,x^3,x^2,x^1,x^0), (," | ", -4,+20,+144, +0), ("-----","--+--","-----","-----","------","----"), (," | ",,-36, -144,color(white)("X")0), ("----","-+","-----","-----","------","-----"), (+9," | ",-4,-16,color(white)("XX")0,), (,,x^2,color(white)("XX")x^1,color(white)("XX")x^0,R) :}#

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How do you divide #(-4x^3 + 20x^2 + 144x)# by #(x -9)#?

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