How do you divide $(2 x^{4} + x^{3} - x^{2} + x - 1) \div (x + 7)$ $(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)$ ?

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How do you divide $(2 x^{4} + x^{3} - x^{2} + x - 1) \div (x + 7)$ $(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)$ ?

1 Answer

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Answer 1 · 2015-07-01T23:43:58

$\frac{2 x^{4} + x^{3} - x^{2} + x - 1}{x + 7} = 2 x^{3} - 13 x^{2} + 90 x - 629 + \frac{4402}{x + 7}$ $(2x^4 +x^3 -x^2 +x -1)/(x+7) = 2x^3 - 13x^2 +90x -629 + 4402/(x+7)$

Explanation:

You use the process of long division.

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So,

$\frac{2 x^{4} + x^{3} - x^{2} + x - 1}{x + 7} = 2 x^{3} - 13 x^{2} + 90 x - 629 + \frac{4402}{x + 7}$ $(2x^4 +x^3 -x^2 +x -1)/(x+7) = 2x^3 - 13x^2 +90x -629 + 4402/(x+7)$

Check:

$(x + 7) (2 x^{3} - 13 x^{2} + 90 x - 629 + \frac{4402}{x + 7}) = (x + 7) (2 x^{3} - 13 x^{2} + 90 x - 629) + 4402$ $(x+7)(2x^3 - 13x^2 +90x -629 + 4402/(x+7)) =(x+7)( 2x^3 - 13x^2 +90x -629) + 4402$

$= 2 x^{4} - 13 x^{3} + 90 x^{2} - 629 x + 14 x^{3} - 91 x^{2} + 630 x - 4403 + 4402 = 2 x^{4} + x^{3} - x^{2} + x - 1$ $= 2x^4 -13x^3 +90x^2 -629x +14x^3 -91x^2 +630x -4403 +4402 = 2x^4 +x^3 -x^2 +x -1$

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How do you divide $(2 x^{4} + x^{3} - x^{2} + x - 1) \div (x + 7)$ $(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)$ ?

1 Answer

Explanation:

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How do you divide (2x4+x3−x2+x−1)÷(x+7)(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)?

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Explanation:

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How do you divide $(2 x^{4} + x^{3} - x^{2} + x - 1) \div (x + 7)$ $(2x^4 + x^3 - x^2 + x - 1) ÷ (x + 7)$ ?