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How do you divide #2m^2 + 3m - 14# by #2m+7#?

1 Answer

Jul 13, 2015

#(2m^2 +3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)#

Explanation:

You use the process of long division.

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So,

#(2m^2 + 3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)#

Check:

#(m+7)(2m^2 – 14m + 101 + 721/(m+7)) =(m+7)( 2m^2 – 14m +101) -721= 2m^3 –cancel(14m²) +101m +cancel(14m²) -98m +707-721 = 2m^3 +3m -14#

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