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How do you differentiate #y=xe^(-kx)#?

1 Answer

Jan 23, 2017

# = e^(-kx) ( 1 - kx)#

Explanation:

use the product rule.

#(xe^(-kx))^prime = (x)^prime e^(-kx) + x (e^(-kx))^prime#

# = e^(-kx) + x (-k)e^(-kx)#

# = e^(-kx) ( 1 - kx)#

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