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How do you differentiate #y=(x^2-4x)^3#?

1 Answer

Nov 16, 2016

#y'=6(x^2-4x)^2(x-2)#

Explanation:

Use the chain rule, which is basically "derivative of the outside times derivative of the inside":

#y=(x^2-4x)^3#

#y'=3(x^2-4x)^2(2x-4)#

Factor a 2 out of the last term to simplify:
#y'=3(x^2-4x)^2(2)(x-2)#

#y'=6(x^2-4x)^2(x-2)#

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