# How do you differentiate y=((x+1)/(x-1))^2?

$y ' = 2 \left(\frac{x + 1}{x - 1}\right) \frac{\left(x - 1\right) - \left(x + 1\right)}{x - 1} ^ 2 =$
$= 2 \left(\frac{x + 1}{x - 1}\right) \frac{- 2}{x - 1} ^ 2 =$
$= - 4 \frac{x + 1}{x - 1} ^ 3$