How do you differentiate #y= ln e^(6x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Ratnaker Mehta Aug 1, 2016 #dy/dx=6#. Explanation: #y=lne^(6x+1)#. But, #lne^t=tlne=t*1=t#. So, #y=6x+1#. #:. dy/dx=6#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1321 views around the world You can reuse this answer Creative Commons License