How do you differentiate #y = e^9 ln x#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Eddie Jun 29, 2016 #= e^9 1/x# Explanation: #e^9# is juat a constant and #d/dx alpha ln x = alpha d/dx ln x = alpha 1/x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1449 views around the world You can reuse this answer Creative Commons License