How do you differentiate y = e^(2x) ln x? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Shwetank Mauria Sep 28, 2016 (dy)/(dx)=e^(2x)(2lnx+1/x) Explanation: To differentiate y=e^(2x)lnx, we use product rule according to which if f(x)=g(x)xxh(x) (df)/(dx)=g(x)xx(dh)/(dx)+(dg)/(dx)xxh(x) As such (dy)/(dx)=(e^(2x)xx2xxlnx)+(e^(2x)xx1/x) = e^(2x)(2lnx+1/x) Answer link Related questions What is the derivative of f(x)=ln(g(x)) ? What is the derivative of f(x)=ln(x^2+x) ? What is the derivative of f(x)=ln(e^x+3) ? What is the derivative of f(x)=x*ln(x) ? What is the derivative of f(x)=e^(4x)*ln(1-x) ? What is the derivative of f(x)=ln(x)/x ? What is the derivative of f(x)=ln(cos(x)) ? What is the derivative of f(x)=ln(tan(x)) ? What is the derivative of f(x)=sqrt(1+ln(x) ? What is the derivative of f(x)=(ln(x))^2 ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 11158 views around the world You can reuse this answer Creative Commons License