How do you differentiate # y =(5x^2-x+1)^(5/2 # using the chain rule?
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1 Answer
Jul 24, 2017
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larr" chain rule"#
#y=(5x^2-x+1)^(5/2)#
#rArrdy/dx=5/2(5x^2-x+1)^(3/2)xxd/dx(5x^2-x+1)#
#color(white)(rArrdy/dx)=5/2(10x-1)(5x^2-x+1)^(3/2)#
