How do you differentiate #x(x-2)^2#?

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Answer 1 · 2015-04-14T12:48:06

Use the Product Rule and the Chain Rule to deal with #()^2#:
#y´=1(x-2)^2+2x(x-2)=#
#=x^2-4x+4+2x^2-4x=3x^2-8x+4#