How do you differentiate #tan(sqrt(2x+5))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer ali ergin Jul 11, 2016 #d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x# Explanation: #y=tan sqrt(2x+5)# #"let's use the chain rule"# #d y=(1+tan^2sqrt(2x+5))* cancel(2)/ (cancel(2)*sqrt((2x+5))) d x# #d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1390 views around the world You can reuse this answer Creative Commons License