How do you differentiate #sqrt(1+(1/x))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Aug 19, 2016 #-1/(2x^2sqrt(1+1/x))# Explanation: #f(x) = sqrt(1+1/x) = (1+1/x)^(1/2)# #f'(x) = 1/2 (1+1/x)^(-1/2) * d/dx(1+1/x)# (Power rule and Chain rule) #f'(x) = 1/(2sqrt(1+1/x)) *(0-1/x^2)# (Power rule) #f'(x) = -1/(2x^2sqrt(1+1/x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1129 views around the world You can reuse this answer Creative Commons License