How do you differentiate #r(x)=e^(6x^2-8x)+1/x#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Sonnhard Jun 17, 2018 #r'(x)=e^(6x^2-8x)*(12x-8)-1/x^2# Explanation: By the chain rule and the sum rule we get #r'(x)=e^(6x^2-8x)(12x-8)-1/x^2# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1425 views around the world You can reuse this answer Creative Commons License