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How do you differentiate #r(x)=(e^(41x^2))^3#?

1 Answer

Oct 27, 2016

# r'(x) = 246xe^(123x^2) #

Explanation:

We have # r = (e^(41x^2))^3 #
# :. r = e^(123x^2) #
# :. (dr)/dx = (123)e^(123x^2)(2x) #
# :. (dr)/dx = 246xe^(123x^2) #

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