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How do you differentiate #ln[(x^4-3x^3+1)^(1/2)] #?

1 Answer

Jun 2, 2018

#y'=(4*x^3-9x^2)/(2*(x^4-3x^3+1))#

Explanation:

By the chain and power rule we get

#1/sqrt(x^4-3x^3+1)*1/2*(x^4-3x^3+1)^(-1/2)*(4x^3-9x^2)#

and this is equal to

#(4x^3-9x^2)/(2*(x^4-3x^3+1))#

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