# How do you differentiate: ln(x^2 +1)?

I found: $\frac{2 x}{{x}^{2} + 1}$
I would use the Chain Rule to dela with $\ln$ first and multiply times the derivative of the argument to get:
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{1}{{x}^{2} + 1} \cdot 2 x = \frac{2 x}{{x}^{2} + 1}$