How do you differentiate #ln (tan (x^2))#?

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How do you differentiate #ln (tan (x^2))#?

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Answer 1 · 2015-03-01T21:27:01

I would use the Chain Rule: first differentiating #ln# as it is then multiply by the #tan# differentiated as it is and at last times #x^2# differentiated:
You get:
#y'=1/(tan(x^2)]*1/(cos^2(x^2))*2x=(2x)/(sin(x^2)cos(x^2)#

(Where #tan(x^2)=sin(x^2)/cos(x^2)#)

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How do you differentiate #ln (tan (x^2))#?

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