How do you differentiate # ln[ (2x^3)-(3x^2)+(7) ]#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Sonnhard Jul 6, 2018 #1/(2*x^3-3*x^2+7)*(6*x^2-6*x)# Explanation: Using the fact that#(ln(x))'=1/x# and the chain rule we get #1/(2x^3-3x^2+7)*(6x^2-6x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1556 views around the world You can reuse this answer Creative Commons License