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How do you differentiate given #sin^2(x/6)#?

1 Answer

Shwetank Mauria

Jun 16, 2016

#(df)/(dx)=sin(x/3)#

Explanation:

As #f(x)=sin^2(x/6)#

Using chain rule, #(df)/(dx)=2sin(x/6)xxcos(x/6)#

Now as #2sinAcosA=sin2A#,

#(df)/(dx)=sin(x/3)#

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