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How do you differentiate #f(x) = x^3(2x-5)^4# using the chain rule?

1 Answer

Apr 11, 2018

#f'(x)=x^2(2x-5)^3(14x-15)#

Explanation:

#f(x)=x^3(2x-5)^4#

#f'(x)=x^3times4(2x-5)^3times2+(2x-5)^4times3x^2#

#f'(x)=(2x-5)^3(8x^3+6x^3-15x^2)#

#f'(x)=(2x-5)^3(14x^3-15x^2)#

#f'(x)=x^2(2x-5)^3(14x-15)#

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