How do you differentiate #f(x)=tansqrtx# using the chain rule?
1 Answer
Dec 26, 2015
You take it from the outside in. You can use the derivative of
#d/(dx)[tanu] = sec^2u ((du)/(dx))# where
#u = sqrtx# .
So:
#(du)/(dx) = d/(dx)[sqrtx] = 1/2*x^("-1/2") = 1/(2sqrtx)#
As a result, you get:
#= color(blue)((sec^2 sqrtx)/(2sqrtx))#
