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How do you differentiate #f(x)=tan(e^(x-x^2)) # using the chain rule?

1 Answer

Jun 17, 2018

#f'(x)=e^(x-x^2)*(1-2x)*sec^2(e^(x-x^2))#

Explanation:

Note that

#(tan(x))'=sec^2(x)#
so we get by the chain rule

#sec^2(e^(x-x^2))*e^(x-x^2)*(1-2x)#

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