How do you differentiate #f(x)=tan(3x-x^2) # using the chain rule?
1 Answer
Sep 13, 2017
Explanation:
#"given "f(x)=g(h(x))" then"#
#f'(x)=g'(h(x))xxh'(x)larr" chain rule"#
#rArrf'(x)=sec^2(3x-x^2)xxd/dx(3x-x^2)#
#color(white)(rArrf'(x))=(3-2x)sec^2(3x-x^2)#
