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How do you differentiate #f(x)=tan(1-3x^2) # using the chain rule?

1 Answer

Jan 10, 2016

#(-6x)sec^2(1 - 3x^2 )#

Explanation:

applying the chain rule as follows :

#f'(x) = sec^2(1 - 3x^2).d/dx(1 - 3x^2 ) #

#f'(x) = sec^2(1 - 3x^2).(- 6x )#

#rArr f'(x) =(-6x)sec^2(1 - 3x^2 ) #

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