How do you differentiate #f(x)=sqrt(ln((x-2)^2)# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bdub Oct 31, 2016 see below Explanation: #f(x)=sqrt(ln((x-2)^2)# #f'(x)=(1/(2sqrtln((x-2)^2))) * 1/(x-2)^2 *2(x-2) *1# #f'(x)=1/((x-2)sqrtln((x-2)^2))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1335 views around the world You can reuse this answer Creative Commons License