How do you differentiate # f(x)=sqrt((7-2x^3)# using the chain rule.? Calculus Basic Differentiation Rules Chain Rule 1 Answer Teddy Jun 29, 2018 #f'(x)=(-3x^2)/sqrt(7-2x^3)# Explanation: Chain rule: #y=f(g(x))->dy/dx=f'(g(x))g'(x)# #d/dx(sqrt(7-2x^3))=1/(2sqrt(7-2x^3))d/dx(7-2x^3)# #:.d/dx(sqrt(7-2x^3))=(-3x^2)/sqrt(7-2x^3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1728 views around the world You can reuse this answer Creative Commons License