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How do you differentiate #f(x)=sinsqrtx# using the chain rule?

1 Answer

Nov 24, 2015

#f'(x)=(cossqrtx)/(2sqrtx)#

Explanation:

According to the Chain Rule:

#f'(x)=cossqrtx*overbrace(d/dx[sqrtx])^(d/dx[x^(1/2)])#

#f'(x)=cossqrtx*1/2x^(-1/2)#

#f'(x)=(cossqrtx)/(2sqrtx)#

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