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How do you differentiate #f(x)=-sinsqrt(1/(x^2))# using the chain rule?

1 Answer

Nov 1, 2016

#f'(x)=-cos(1/x)/x^2#

Explanation:

#f(x)=-sinsqrt(1/x^2) = -sin (x^-2)^(1/2)=sinx^-1#

#f'(x)=cos(1/x)*-1/x^2#

#f'(x)=-cos(1/x)/x^2#

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