# How do you differentiate #f(x)=(sin2x^2)/4# using the chain rule?

##### 1 Answer

Feb 9, 2016

#### Explanation:

According to the chain rule, since the derivative of

Formally, this can be written as

#d/dx[sin(g(x))]=cos(g(x))*g'(x)#

Here, notice first that

#f'(x)=1/4cos(2x^2)*d/dx[2x^2]#

Since the derivative of

#f'(x)=1/4cos(2x^2)*4x#

The

#f'(x)=xcos(2x^2)#