How do you differentiate f(x)=sin(e^(3x^3-x))  using the chain rule?

$\frac{d}{d x} f \left(x\right) = {e}^{3 {x}^{3} - x} \cdot \left(9 {x}^{2} - 1\right) \cdot \cos \left({e}^{3 {x}^{3} - x}\right) \cdot l n \left(e\right)$
$f \left(x\right) = \sin \left({e}^{3 {x}^{3} - x}\right)$
$\frac{d}{d x} f \left(x\right) = {e}^{3 {x}^{3} - x} \cdot \left(9 {x}^{2} - 1\right) \cdot \cos \left({e}^{3 {x}^{3} - x}\right) \cdot l n \left(e\right)$