How do you differentiate f(x)=sin(4-x^2) using the chain rule?

1 Answer

f' (x)=-2x*cos (4-x^2)

Explanation:

The solution :

The formula for differentiating sin u for any differentiable function u is

d/dx(sin u)=cos u d/dx(u)

The given: f(x)=sin (4-x^2)

f' (x)=d/dx(sin (4-x^2))=cos (4-x^2) d/dx(4-x^2)

f' (x)=cos (4-x^2) *(-2x)

f' (x)=-2x*cos (4-x^2)

God bless....I hope the explanation is useful.