How do you differentiate #f(x)=sin(2x^3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Anjali G Nov 9, 2016 #f(x)=sin(2x^3)# Chain rule: #f'(x)=(cos(2x^3))(6x^2)# #f'(x)=6x^2cos(2x^3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2409 views around the world You can reuse this answer Creative Commons License