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How do you differentiate #f(x)=sin^2(1/x)^2# using the chain rule?

1 Answer

Jun 10, 2018

#-(4sin(1/x^2)cos(1/x^2))/x^3#

Explanation:

Writing your function in the form

#(sin(1/x^2))^2#
and we get by the power and the chain rule

#2sin(1/x^2)cos(1/x^2)*2(1/x)*(-1/x^2)#
this is

#-(4sin(1/x^2)*cos(1/x^2))/x^3#

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