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How do you differentiate #f(x)=sec^4(x^3-x^2 ) # using the chain rule?

1 Answer

Nov 1, 2016

#f'(x)=4(3x^2-2x)sec^4(x^3-x^2)tan(x^3-x^2)#

Explanation:

#f(x)=sec^4(x^3-x^2)=(sec(x^3-x^2))^4#

#f'(x)=4(sec(x^3-x^2))^3*sec(x^3-x^2))tan(x^3-x^2)*(3x^2-2x)#

#f'(x)=4(3x^2-2x)sec^4(x^3-x^2)tan(x^3-x^2)#

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