How do you differentiate #f(x)=ln (x^3+3)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Steve M Oct 31, 2016 # f'(x) = (3x^2)/(x^3+3)# Explanation: # f(x) = ln(x^3+3) # To differentiate we use the chain rule: # d/dxf(g(x)) =f'(g(x))g'(x)# or,# dy/dx=dy/(du)(du)/dx# # :. f'(x) = 1/(x^3+3) d/dx(x^3+3)# # :. f'(x) = 1/(x^3+3)(3x^2)# # :. f'(x) = (3x^2)/(x^3+3)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 2468 views around the world You can reuse this answer Creative Commons License