How do you differentiate #f(x)=ln(x^2-sqrt(2x+8)))# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Trevor Ryan. Jan 3, 2016 #f'(x)=2/(x^2-sqrt(2x+8)) * (2x-1/2(2x+8)^(-1/2))# Explanation: #f'(x)=1/(x^2-sqrt(2x+8)) * (2x-1/2(2x+8)^(-1/2)) * (2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1143 views around the world You can reuse this answer Creative Commons License