# How do you differentiate f(x)=ln(cotx) using the chain rule?

$\frac{d}{\mathrm{dx}} \left[\ln \left(\cot x\right)\right] = \frac{- \cos e {c}^{2} x}{\cot x}$
$\frac{d}{\mathrm{dx}} \left[\ln \left(\cot x\right)\right] = \frac{1}{\cot} x \cdot \frac{d}{\mathrm{dx}} \cot x$
$= \frac{- \cos e {c}^{2} x}{\cot x}$