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How do you differentiate #f(x)=ln(cotx)# using the chain rule?

1 Answer

Nov 10, 2015

#d/dx[ln(cotx)]=(-cosec^2x)/(cotx)#

Explanation:

#d/dx[ln(cotx)]=1/cotx*d/dxcotx#

#=(-cosec^2x)/(cotx)#

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